3.1102 \(\int \frac{A+B x}{(a+b x) (d+e x)^3} \, dx\)

Optimal. Leaf size=112 \[ \frac{A b-a B}{(d+e x) (b d-a e)^2}-\frac{B d-A e}{2 e (d+e x)^2 (b d-a e)}+\frac{b (A b-a B) \log (a+b x)}{(b d-a e)^3}-\frac{b (A b-a B) \log (d+e x)}{(b d-a e)^3} \]

[Out]

-(B*d - A*e)/(2*e*(b*d - a*e)*(d + e*x)^2) + (A*b - a*B)/((b*d - a*e)^2*(d + e*x
)) + (b*(A*b - a*B)*Log[a + b*x])/(b*d - a*e)^3 - (b*(A*b - a*B)*Log[d + e*x])/(
b*d - a*e)^3

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Rubi [A]  time = 0.198713, antiderivative size = 112, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.05 \[ \frac{A b-a B}{(d+e x) (b d-a e)^2}-\frac{B d-A e}{2 e (d+e x)^2 (b d-a e)}+\frac{b (A b-a B) \log (a+b x)}{(b d-a e)^3}-\frac{b (A b-a B) \log (d+e x)}{(b d-a e)^3} \]

Antiderivative was successfully verified.

[In]  Int[(A + B*x)/((a + b*x)*(d + e*x)^3),x]

[Out]

-(B*d - A*e)/(2*e*(b*d - a*e)*(d + e*x)^2) + (A*b - a*B)/((b*d - a*e)^2*(d + e*x
)) + (b*(A*b - a*B)*Log[a + b*x])/(b*d - a*e)^3 - (b*(A*b - a*B)*Log[d + e*x])/(
b*d - a*e)^3

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Rubi in Sympy [A]  time = 30.1428, size = 90, normalized size = 0.8 \[ - \frac{b \left (A b - B a\right ) \log{\left (a + b x \right )}}{\left (a e - b d\right )^{3}} + \frac{b \left (A b - B a\right ) \log{\left (d + e x \right )}}{\left (a e - b d\right )^{3}} + \frac{A b - B a}{\left (d + e x\right ) \left (a e - b d\right )^{2}} - \frac{A e - B d}{2 e \left (d + e x\right )^{2} \left (a e - b d\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate((B*x+A)/(b*x+a)/(e*x+d)**3,x)

[Out]

-b*(A*b - B*a)*log(a + b*x)/(a*e - b*d)**3 + b*(A*b - B*a)*log(d + e*x)/(a*e - b
*d)**3 + (A*b - B*a)/((d + e*x)*(a*e - b*d)**2) - (A*e - B*d)/(2*e*(d + e*x)**2*
(a*e - b*d))

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Mathematica [A]  time = 0.168621, size = 112, normalized size = 1. \[ \frac{A b-a B}{(d+e x) (b d-a e)^2}+\frac{B d-A e}{2 e (d+e x)^2 (a e-b d)}+\frac{b (A b-a B) \log (a+b x)}{(b d-a e)^3}-\frac{b (A b-a B) \log (d+e x)}{(b d-a e)^3} \]

Antiderivative was successfully verified.

[In]  Integrate[(A + B*x)/((a + b*x)*(d + e*x)^3),x]

[Out]

(B*d - A*e)/(2*e*(-(b*d) + a*e)*(d + e*x)^2) + (A*b - a*B)/((b*d - a*e)^2*(d + e
*x)) + (b*(A*b - a*B)*Log[a + b*x])/(b*d - a*e)^3 - (b*(A*b - a*B)*Log[d + e*x])
/(b*d - a*e)^3

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Maple [A]  time = 0.016, size = 171, normalized size = 1.5 \[ -{\frac{A}{ \left ( 2\,ae-2\,bd \right ) \left ( ex+d \right ) ^{2}}}+{\frac{Bd}{ \left ( 2\,ae-2\,bd \right ) e \left ( ex+d \right ) ^{2}}}+{\frac{{b}^{2}\ln \left ( ex+d \right ) A}{ \left ( ae-bd \right ) ^{3}}}-{\frac{b\ln \left ( ex+d \right ) Ba}{ \left ( ae-bd \right ) ^{3}}}+{\frac{Ab}{ \left ( ae-bd \right ) ^{2} \left ( ex+d \right ) }}-{\frac{Ba}{ \left ( ae-bd \right ) ^{2} \left ( ex+d \right ) }}-{\frac{{b}^{2}\ln \left ( bx+a \right ) A}{ \left ( ae-bd \right ) ^{3}}}+{\frac{b\ln \left ( bx+a \right ) Ba}{ \left ( ae-bd \right ) ^{3}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int((B*x+A)/(b*x+a)/(e*x+d)^3,x)

[Out]

-1/2/(a*e-b*d)/(e*x+d)^2*A+1/2/(a*e-b*d)/e/(e*x+d)^2*B*d+b^2/(a*e-b*d)^3*ln(e*x+
d)*A-b/(a*e-b*d)^3*ln(e*x+d)*B*a+1/(a*e-b*d)^2/(e*x+d)*A*b-1/(a*e-b*d)^2/(e*x+d)
*B*a-b^2/(a*e-b*d)^3*ln(b*x+a)*A+b/(a*e-b*d)^3*ln(b*x+a)*B*a

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Maxima [A]  time = 1.38007, size = 333, normalized size = 2.97 \[ -\frac{{\left (B a b - A b^{2}\right )} \log \left (b x + a\right )}{b^{3} d^{3} - 3 \, a b^{2} d^{2} e + 3 \, a^{2} b d e^{2} - a^{3} e^{3}} + \frac{{\left (B a b - A b^{2}\right )} \log \left (e x + d\right )}{b^{3} d^{3} - 3 \, a b^{2} d^{2} e + 3 \, a^{2} b d e^{2} - a^{3} e^{3}} - \frac{B b d^{2} + A a e^{2} + 2 \,{\left (B a - A b\right )} e^{2} x +{\left (B a - 3 \, A b\right )} d e}{2 \,{\left (b^{2} d^{4} e - 2 \, a b d^{3} e^{2} + a^{2} d^{2} e^{3} +{\left (b^{2} d^{2} e^{3} - 2 \, a b d e^{4} + a^{2} e^{5}\right )} x^{2} + 2 \,{\left (b^{2} d^{3} e^{2} - 2 \, a b d^{2} e^{3} + a^{2} d e^{4}\right )} x\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x + A)/((b*x + a)*(e*x + d)^3),x, algorithm="maxima")

[Out]

-(B*a*b - A*b^2)*log(b*x + a)/(b^3*d^3 - 3*a*b^2*d^2*e + 3*a^2*b*d*e^2 - a^3*e^3
) + (B*a*b - A*b^2)*log(e*x + d)/(b^3*d^3 - 3*a*b^2*d^2*e + 3*a^2*b*d*e^2 - a^3*
e^3) - 1/2*(B*b*d^2 + A*a*e^2 + 2*(B*a - A*b)*e^2*x + (B*a - 3*A*b)*d*e)/(b^2*d^
4*e - 2*a*b*d^3*e^2 + a^2*d^2*e^3 + (b^2*d^2*e^3 - 2*a*b*d*e^4 + a^2*e^5)*x^2 +
2*(b^2*d^3*e^2 - 2*a*b*d^2*e^3 + a^2*d*e^4)*x)

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Fricas [A]  time = 0.214324, size = 463, normalized size = 4.13 \[ -\frac{B b^{2} d^{3} - 3 \, A b^{2} d^{2} e - A a^{2} e^{3} -{\left (B a^{2} - 4 \, A a b\right )} d e^{2} + 2 \,{\left ({\left (B a b - A b^{2}\right )} d e^{2} -{\left (B a^{2} - A a b\right )} e^{3}\right )} x + 2 \,{\left ({\left (B a b - A b^{2}\right )} e^{3} x^{2} + 2 \,{\left (B a b - A b^{2}\right )} d e^{2} x +{\left (B a b - A b^{2}\right )} d^{2} e\right )} \log \left (b x + a\right ) - 2 \,{\left ({\left (B a b - A b^{2}\right )} e^{3} x^{2} + 2 \,{\left (B a b - A b^{2}\right )} d e^{2} x +{\left (B a b - A b^{2}\right )} d^{2} e\right )} \log \left (e x + d\right )}{2 \,{\left (b^{3} d^{5} e - 3 \, a b^{2} d^{4} e^{2} + 3 \, a^{2} b d^{3} e^{3} - a^{3} d^{2} e^{4} +{\left (b^{3} d^{3} e^{3} - 3 \, a b^{2} d^{2} e^{4} + 3 \, a^{2} b d e^{5} - a^{3} e^{6}\right )} x^{2} + 2 \,{\left (b^{3} d^{4} e^{2} - 3 \, a b^{2} d^{3} e^{3} + 3 \, a^{2} b d^{2} e^{4} - a^{3} d e^{5}\right )} x\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x + A)/((b*x + a)*(e*x + d)^3),x, algorithm="fricas")

[Out]

-1/2*(B*b^2*d^3 - 3*A*b^2*d^2*e - A*a^2*e^3 - (B*a^2 - 4*A*a*b)*d*e^2 + 2*((B*a*
b - A*b^2)*d*e^2 - (B*a^2 - A*a*b)*e^3)*x + 2*((B*a*b - A*b^2)*e^3*x^2 + 2*(B*a*
b - A*b^2)*d*e^2*x + (B*a*b - A*b^2)*d^2*e)*log(b*x + a) - 2*((B*a*b - A*b^2)*e^
3*x^2 + 2*(B*a*b - A*b^2)*d*e^2*x + (B*a*b - A*b^2)*d^2*e)*log(e*x + d))/(b^3*d^
5*e - 3*a*b^2*d^4*e^2 + 3*a^2*b*d^3*e^3 - a^3*d^2*e^4 + (b^3*d^3*e^3 - 3*a*b^2*d
^2*e^4 + 3*a^2*b*d*e^5 - a^3*e^6)*x^2 + 2*(b^3*d^4*e^2 - 3*a*b^2*d^3*e^3 + 3*a^2
*b*d^2*e^4 - a^3*d*e^5)*x)

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Sympy [A]  time = 7.95817, size = 558, normalized size = 4.98 \[ - \frac{b \left (- A b + B a\right ) \log{\left (x + \frac{- A a b^{2} e - A b^{3} d + B a^{2} b e + B a b^{2} d - \frac{a^{4} b e^{4} \left (- A b + B a\right )}{\left (a e - b d\right )^{3}} + \frac{4 a^{3} b^{2} d e^{3} \left (- A b + B a\right )}{\left (a e - b d\right )^{3}} - \frac{6 a^{2} b^{3} d^{2} e^{2} \left (- A b + B a\right )}{\left (a e - b d\right )^{3}} + \frac{4 a b^{4} d^{3} e \left (- A b + B a\right )}{\left (a e - b d\right )^{3}} - \frac{b^{5} d^{4} \left (- A b + B a\right )}{\left (a e - b d\right )^{3}}}{- 2 A b^{3} e + 2 B a b^{2} e} \right )}}{\left (a e - b d\right )^{3}} + \frac{b \left (- A b + B a\right ) \log{\left (x + \frac{- A a b^{2} e - A b^{3} d + B a^{2} b e + B a b^{2} d + \frac{a^{4} b e^{4} \left (- A b + B a\right )}{\left (a e - b d\right )^{3}} - \frac{4 a^{3} b^{2} d e^{3} \left (- A b + B a\right )}{\left (a e - b d\right )^{3}} + \frac{6 a^{2} b^{3} d^{2} e^{2} \left (- A b + B a\right )}{\left (a e - b d\right )^{3}} - \frac{4 a b^{4} d^{3} e \left (- A b + B a\right )}{\left (a e - b d\right )^{3}} + \frac{b^{5} d^{4} \left (- A b + B a\right )}{\left (a e - b d\right )^{3}}}{- 2 A b^{3} e + 2 B a b^{2} e} \right )}}{\left (a e - b d\right )^{3}} - \frac{A a e^{2} - 3 A b d e + B a d e + B b d^{2} + x \left (- 2 A b e^{2} + 2 B a e^{2}\right )}{2 a^{2} d^{2} e^{3} - 4 a b d^{3} e^{2} + 2 b^{2} d^{4} e + x^{2} \left (2 a^{2} e^{5} - 4 a b d e^{4} + 2 b^{2} d^{2} e^{3}\right ) + x \left (4 a^{2} d e^{4} - 8 a b d^{2} e^{3} + 4 b^{2} d^{3} e^{2}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x+A)/(b*x+a)/(e*x+d)**3,x)

[Out]

-b*(-A*b + B*a)*log(x + (-A*a*b**2*e - A*b**3*d + B*a**2*b*e + B*a*b**2*d - a**4
*b*e**4*(-A*b + B*a)/(a*e - b*d)**3 + 4*a**3*b**2*d*e**3*(-A*b + B*a)/(a*e - b*d
)**3 - 6*a**2*b**3*d**2*e**2*(-A*b + B*a)/(a*e - b*d)**3 + 4*a*b**4*d**3*e*(-A*b
+ B*a)/(a*e - b*d)**3 - b**5*d**4*(-A*b + B*a)/(a*e - b*d)**3)/(-2*A*b**3*e + 2
*B*a*b**2*e))/(a*e - b*d)**3 + b*(-A*b + B*a)*log(x + (-A*a*b**2*e - A*b**3*d +
B*a**2*b*e + B*a*b**2*d + a**4*b*e**4*(-A*b + B*a)/(a*e - b*d)**3 - 4*a**3*b**2*
d*e**3*(-A*b + B*a)/(a*e - b*d)**3 + 6*a**2*b**3*d**2*e**2*(-A*b + B*a)/(a*e - b
*d)**3 - 4*a*b**4*d**3*e*(-A*b + B*a)/(a*e - b*d)**3 + b**5*d**4*(-A*b + B*a)/(a
*e - b*d)**3)/(-2*A*b**3*e + 2*B*a*b**2*e))/(a*e - b*d)**3 - (A*a*e**2 - 3*A*b*d
*e + B*a*d*e + B*b*d**2 + x*(-2*A*b*e**2 + 2*B*a*e**2))/(2*a**2*d**2*e**3 - 4*a*
b*d**3*e**2 + 2*b**2*d**4*e + x**2*(2*a**2*e**5 - 4*a*b*d*e**4 + 2*b**2*d**2*e**
3) + x*(4*a**2*d*e**4 - 8*a*b*d**2*e**3 + 4*b**2*d**3*e**2))

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GIAC/XCAS [A]  time = 0.215593, size = 308, normalized size = 2.75 \[ -\frac{{\left (B a b^{2} - A b^{3}\right )}{\rm ln}\left ({\left | b x + a \right |}\right )}{b^{4} d^{3} - 3 \, a b^{3} d^{2} e + 3 \, a^{2} b^{2} d e^{2} - a^{3} b e^{3}} + \frac{{\left (B a b e - A b^{2} e\right )}{\rm ln}\left ({\left | x e + d \right |}\right )}{b^{3} d^{3} e - 3 \, a b^{2} d^{2} e^{2} + 3 \, a^{2} b d e^{3} - a^{3} e^{4}} - \frac{{\left (B b^{2} d^{3} - 3 \, A b^{2} d^{2} e - B a^{2} d e^{2} + 4 \, A a b d e^{2} - A a^{2} e^{3} + 2 \,{\left (B a b d e^{2} - A b^{2} d e^{2} - B a^{2} e^{3} + A a b e^{3}\right )} x\right )} e^{\left (-1\right )}}{2 \,{\left (b d - a e\right )}^{3}{\left (x e + d\right )}^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x + A)/((b*x + a)*(e*x + d)^3),x, algorithm="giac")

[Out]

-(B*a*b^2 - A*b^3)*ln(abs(b*x + a))/(b^4*d^3 - 3*a*b^3*d^2*e + 3*a^2*b^2*d*e^2 -
a^3*b*e^3) + (B*a*b*e - A*b^2*e)*ln(abs(x*e + d))/(b^3*d^3*e - 3*a*b^2*d^2*e^2
+ 3*a^2*b*d*e^3 - a^3*e^4) - 1/2*(B*b^2*d^3 - 3*A*b^2*d^2*e - B*a^2*d*e^2 + 4*A*
a*b*d*e^2 - A*a^2*e^3 + 2*(B*a*b*d*e^2 - A*b^2*d*e^2 - B*a^2*e^3 + A*a*b*e^3)*x)
*e^(-1)/((b*d - a*e)^3*(x*e + d)^2)